552s+552s+11040=(23s^2)+460s

Solution for 552s+552s+11040=(23s^2)+460s equation:

552s+552s+11040=(23s^2)+460s

We move all terms to the left:

552s+552s+11040-((23s^2)+460s)=0

We add all the numbers together, and all the variables

1104s-(23s^2+460s)+11040=0

We get rid of parentheses

-23s^2+1104s-460s+11040=0

We add all the numbers together, and all the variables

-23s^2+644s+11040=0

a = -23; b = 644; c = +11040;
Δ = b2-4ac
Δ = 6442-4·(-23)·11040
Δ = 1430416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1430416}=1196$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(644)-1196}{2*-23}=\frac{-1840}{-46}
=+40
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(644)+1196}{2*-23}=\frac{552}{-46}
=-12
$